Question #80ec8

1 Answer
Dec 8, 2017

#pi/6; (5pi)/6; (13pi)/6; (17pi)/6#

Explanation:

2sin t - 1 = 0 --> 2sin t = 1
#sin t = 1/2#
Trig table gives --> #t = pi/6 + 2kpi#
Unit circle gives another arc t that has the same sin value (1/2) -->
#t = pi - pi/6 = (5pi)/6 + 2kpi#
Answers in interval (0, 3pi), with k = 0, and k = 1
#pi/6; (5pi)/6; pi/6 + 2pi = (13pi)/6; (5pi)/6 + 2pi = (17pi)/6#