Question #330f8

1 Answer
Dec 8, 2017

#20^@; 100^@#

Explanation:

2cos 3t - 1 = 0
2cos 3t = 1
#cos 3t = 1/2#
Trig table and unit circle give 2 solutions:
#3t =+- pi/3#
a. #3t = pi/3# --> #t = pi/9, or t = 20^@#
b. #3t = (5pi)/3# (co-terminal to #- pi/3#)
#t = (5pi)/9 , or t = 100^@#