Question #0ad18

1 Answer
Nghi N
Dec 10, 2017

Equation insolvable.

Explanation:

#2tan (x/2) + 1/sin x = 0#
Use trig identity:
#tan (x/2) = (1 - cos x)/sin x#
We get:
#(2(1 - cos x))/sin x + 1/sin x = 0#
#2(1 - cos x) + 1 = 0# (condition #sin x != 0#)
#2 - 2cos x + 1 = 0# --> 2cos x = 3
#cos x = 3/2# . Rejected as > 1.
The equation is insolvable.

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