What are the sets of quantum numbers that describe the last three electrons of N?
1 Answer
Here's what I got.
Explanation:
For starters, you know that nitrogen is located in the second period of the Periodic Table, which implies that its outermost electrons are located in the second energy shell.
Moreover, the fact that nitrogen is located in group
Now, the second energy shell is comprised of the
The
This means that the remaining
Now, Hund's Rule states that all the orbitals present in a given energy subshell must be half-filled before any one of those orbitals can be completely filled.
Since you have
So, you can say that the quantum number sets that will describe these electrons will be
#n = 2, l = 1, m_l = -1, m_s = +1/2# This set describes an electron that is located in the second energy shell, in the
#2p# subshell, in the#2p_y# orbital and that has spin-up
#n = 2, l =1, m_l = 0, m_s = +1/2# This set describes an electron that is located in the second energy shell, in the
#2p# subshell, in the#2p_z# orbital and that has spin-up
#n =2 , l =1, m_l = +1, m_s = +1/2# This set describes an electron that is located in the second energy shell, in the
#2p# subshell, in the#2p_x# orbital and that has spin-up
By convention, an electron added to an empty orbital is assigned spin-up, which is why all three electrons have the spin quantum number,
Notice that the principal quantum number,