Question #2bb5c

1 Answer
Dec 22, 2017

Lim_(xrarr1)lnx/(1-x)=-1

Explanation:

log_ex=lnx

Lim_(xrarr1)lnx/(1-x)=0/0

We can use L'Hopitals rule

Lim_(xrarr1)(1/x)/(-1)=Lim_(xrarr1)-1/x=-1/1=-1