Question #b15f5

1 Answer
Dec 27, 2017


You're close!


The name you have written down for this compound is actually a little off because anionic ligands follow a different naming convention.

When an anion that ends in -ide, like the chloride anion, is a ligand, its suffix changes to -o. So instead of dichloride, you must say dichloro.

Also, keep in mind that the name of the ligands and the name of the metal cation are written without added spaces. So instead of

diammine dichloro platinum(II)

you should have


And that's pretty much it.

#"Pt"(color(red)("NH"_ 3))_ color(green)(2) color(darkorange)("Cl")_ color(blue)(2) -> color(green)("di")color(red)("ammine")color(blue)("di")color(darkorange)("chloro")"platinum"("II")#

Notice that you're dealing with a neutral compound here because the #2+# charge of the platinum(I)) cation is balanced out by the #1-# charge on the two chloro ligands. The ammonia molecules are neutral, so they don't affect the charge of the coordination compound in any way.

As a final note, it's worth pointing out that this compound has a cis isomer and a trans isomer and that its cis isomer is actually known as cisplatin #-># see here.