# Question #70f00

Dec 31, 2017

The velocity will be increased by 2 times.

#### Explanation:

Here,the KE of a body is increased by 4 times

$K E ' = 4 K E$

$\mathmr{and} , \frac{1}{2} {\left(m v '\right)}^{2} = 4 \times \frac{1}{2} m {v}^{2}$

$\mathmr{and} , {\left(v '\right)}^{2} = 4 {v}^{2}$

$\therefore v ' = 2 v$