# Question #c9a3b

See Below.

#### Explanation:

$2 {m}^{2} + 2 m - 12 = 0$

$\Rightarrow 2 {m}^{2} + \left(6 - 4\right) m - 12 = 0$ [First factorise the left hand expression]

$\Rightarrow 2 {m}^{2} + 6 m - 4 m - 12 = 0$ [I choose 6 and 4 because $6 \cdot 4 = 2 \cdot 12$, and $6 - 4 = 2$]

$\Rightarrow 2 m \left(m + 3\right) - 4 \left(m + 3\right) = 0$ [Group the like terms]

$\Rightarrow \left(m + 3\right) \left(2 m - 4\right) = 0$ [Take the common part]

$\Rightarrow 2 \left(m + 3\right) \left(m - 2\right) = 0$

$\Rightarrow \left(m + 3\right) \left(m - 2\right) = 0$

If two numbers are multiplied and the answer is zero, then either of them must be zero or both of them.

So, Either, $m + 3 = 0$

$\Rightarrow m = - 3$

Or, $m - 2 = 0$

$\Rightarrow m = 2$

The solution of the quadratic equation is $m = - 3 , 2$