The solution of Iron (III) Chloride is 0.15 M,
So it contains
The solution of Sodium Carbonate is also 0.15 M.
So, it contains
Lets Check The Undergoing Equation Now.
So, 3 moles of
So, The liniting reactant is indeed the sodium carbonate.
So, If The Sodium Carbonate Runs Out, The Reaction will stop.
Let's Approach with the simplest method in existence, The One and Only, Unitary Method.
First, start off with the skeleton equation:
Then, balance the equation to determine the mole ratios:
We now know that, in this reaction, for every
If we know the number of moles for one reactant, we can predict the number of moles for all the other reactants and products.
However, in this problem, there's a twist—amounts for two reactants are given.
This means that one of these reactants is a limiting reactant.
To find out which is the limiting reactant, first determine the number of moles that react for each reactant.
- For iron(III) chloride,
#"0.15 moles = 1000 mL"#
#"15 mL"= 0.15*15/1000 = "0.00225 moles"#.
- For sodium carbonate,
#"1000 mL = 0.15 moles"#
#"20 mL" = 0.15 * 20/1000 = "0.003 moles"#
Recall that in the mole ratio,
To react with
To react with
We only have
Then, just use the moles of the limiting reactant to find out the moles of the product. We use the limiting reactant because all of it reacts.
The molar mass of iron(III) carbonate is