# Question #84c3c

##### 1 Answer

Jan 12, 2018

#### Explanation:

We must divide the equation in two different parts for this we must discover the zeros of

It is easy to see that #x^2−1=(x+1)(x-1), so the zeros are 1 and -1.

Between the zeros the expression is negative so its modulus is:

Solving:

Outside the zeros:

Temos de calcular os zeros desta expressão:

so:

This is equivalent to

Joining both cases we obtain