Question

Question #712b6

Answer 1

Use the identity `sin(2x) = 2sinxcosx`.

a)

`2sinxcosx- sinx = 0`

`sinx(2cosx- 1) = 0`

`sinx= 0 or cosx =1/2`

`x= 0, pi, 2pi, pi/3, (5pi)/3`

b)

`2(2sinxcosx) = 1`

`2sinxcosx= 1/2`

`sin(2x) = 1/2`

`2x = pi/6, (5pi)/6, (13pi)/6, (17pi)/6`

`x = pi/12, (5pi)/12, (13pi)/12, (17pi)/12`

Hopefully this helps!