Question #d2b73

1 Answer
Jan 22, 2018

The oxidation number of Mn in permanganate ion is +7.

Explanation:

The sum of O.N of all atoms of an ion is equal to the charge.
In permanganate ion (MnO_4^-MnO4), there are four O atoms and one Mn atom.

Let's take O.N of Mn as x. O.N of oxygen is usually taken as -2.

x+(-2)*4=-1 x+(2)4=1
x=+7x=+7