Question #401ba

Jan 23, 2018

it is 1. ${x}^{0} = 1 , \forall x \ne 0$

Explanation:

Example:

${\left(- 2\right)}^{0} = {\left(- 2\right)}^{3} / {\left(- 2\right)}^{3} = \frac{- {2}^{3}}{- {2}^{3}} = 1$

Jan 23, 2018

See explanation.

Explanation:

Any number different from zero raised to $0$ equals to $1$

The proof could be as follows:

${a}^{0} = {a}^{b - b} = \frac{{a}^{b}}{{a}^{b}} = 1$

The above calculations are true for all $a \ne 0$ and all $b$ (including $b = 0$)