# Question #97e4c

Jan 26, 2018

#### Answer:

$\text{MgO}$ is the empirical formula.

#### Explanation:

$\text{mol of Mg" = "4.9 g" /"24 g/mol" = "0.2 mol}$

$\text{mol of O" = "3.2 g"/"16 g/mol" = "0.2 mol}$

So the mole ratio is

$0.2 : 0.2 = 1 : 1$

Therefore, $\text{Mg"_1"O"_1 = "MgO}$ is the empirical formula.