# Question #1830f

Feb 3, 2018

$73 g$

#### Explanation:

The formula for density, where density is $\rho$, is $\rho = \frac{m}{V}$.

$m$ is the mass, and $V$ the volume.

The formula can be rearranged as: $m = \rho V$.

So for liquid A:

$m = \rho V$

$m = 1.44 \cdot 25$

$m = 36 g$

For liqiud B:

$m = \rho V$

$m = 1.48 \cdot 25$

$m = 37 g$

We have $36 g$ of one liquid and $37 g$ of the other.

Totally, we have $36 + 37 = 73 g$ of liquid.

Feb 3, 2018

$= 73 g$

#### Explanation:

1. This can be solved using the density formula; i.e.,

$m = \rho \times V$
where:

$m = \text{mass expressed in g}$
$\rho = \text{density expressed in g/ml}$
$V = \text{volume expressed in mL}$

2. Assuming that the liquids are miscible, the mass of the liquids in the flask is computed as follows:

${m}_{t} = m L i q u i {d}_{A} + m L i q u i {d}_{B}$

${m}_{t} = \left(\left({\rho}_{A}\right) \left({V}_{A}\right) + \left({\rho}_{B}\right) \left({V}_{B}\right)\right)$

${m}_{t} = \left(\frac{1.44 g}{\cancel{m l}} \times 25 \cancel{m l}\right) + \left(\frac{1.48 g}{\cancel{m l}} \times 25 \cancel{m l}\right)$

${m}_{t} = 36 g + 37 g$

${m}_{t} = 73 g$