At $-35$ $""^@C$ , and $5.8*atm$ pressure, how many moles of gas are present?

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Answer 1 · 2018-02-01T16:41:45

Let us assume that you have a volume of $1*L$ ...I make it about $0.2*mol$ ..........

And we must assume a volume because, pressure is a state function of volume, temperature, and amount of gas...

And we must use absolute temperature.... $-35$ $""^@C$ $-=$ $308.15*K$ ...and so...

$n=(PV)/(RT)=(5.8*cancel(atm)xx1*cancelL)/(0.0821*cancel(L*atm)*cancel(K^-1)*mol^-1xx308.15*cancelK)$ ...

$=??*mol$

...we get an answer in $1/(mol^-1)-=1/(1/(mol))=mol$ as required...

At -35-35 ""^@C""^@C, and 5.8*atm5.8*atm pressure, how many moles of gas are present?