Question #c0970

2 Answers
Feb 1, 2018

Answer:

#1.63 "mol"# of sodium chloride.

Explanation:

Remember that the formula for moles, #n#, is #n=m/M#, where #m# is the mass of the substance, and #M# its molar mass.

Therefore, we must first calculate the mass of #NaCl# present.

To do this, we can use the formula for density, #rho#, when #rho=m/V#, where #V# is the volume of liquid.

The density of sodium chloride is #2.16g/(mL)#.

So input: #2.16=m/44#

#2.16*44=m/44*44#

#m=95.04g# of sodium chloride.

Now we may use #n=m/M#.

The molar mass of sodium chloride is #58.4g/("mol")#.

So simply input: #n=95.04/58.4#

#n=1.63 "mol"# of sodium chloride.

Feb 1, 2018

Answer:

#~~1.63mol#

Explanation:

Well, we'll need a few steps here...

First, know that #1mL=1cm^3#, so

#44mL=44cm^3#

Now, we can use the density equation to find the mass of the sodium chloride:

#rho=m/V# or #m=rho*V#

The density of sodium chloride is #2.16g"/"cm^3#

#:."mass"=2.16g"/"cm^3*44cm^3=95.04g#

So, we have #95.04g# of sodium chloride.

Next, we have to use the molar mass formula to find the amount of moles.

#"moles"="mass"/"molar mass"#

The molar mass of sodium chloride is #58.4g"/"mol#.

#:."moles"=(95.04cancelg)/(58.4cancelg"/"mol)~~1.63mol#

So, our final answer is #1.63# moles of sodium chloride.