Question #4b672

1 Answer
Feb 1, 2018

I couldn't find in trig books any formula of (sec a - sec b).
However, I think we can create one.
Starting from trig identity,
#cos a - cos b = - 2sin ((a+b)/2)sin ((a - b)/2)#
we can write:
#1/(cos a) - 1/(cos b) = (cos b - cos a)/(cos a.cos b)#
#sec a - sec b = [2sin ((a + b)/2).sin ((a - b)/2)]/(cos a.cos b)#
Example: #a = pi/3, and b = pi/4# -->
#(a + b)/2 = (7pi)/24# , and #(a - b)/2 = pi/24#, and
#cos a.cos b = (sqrt2/2)(1/2) = sqrt2/4#.
Finally, we get:
#sec (pi/3) - sec(pi/4) = 2[sin ((7pi)/24).sin (pi/24)]/(sqrt2/4)#