Question

What mass of carbon dioxide results from the complete combustion of `359*g` propane, and `359*g` methane?

Answer 1

Approx. `1*kg`...

Explanation:

We assume complete combustion according to (i):

`CH_4(g) +2O_2(g) rarr CO_2(g) +2H_2O(l)`

`"Moles of methane"=(359*gxx32.6%)/(16.04*g)=7.30*mol`

And (ii):

`C_2H_6(g) +7/2O_2(g) rarr 2CO_2(g) +3H_2O(l)`

`"Moles of propane"=(359*gxx67.4%)/(30.04*g)=8.05*mol`

And so, WITH RESPECT to carbon dioxide, we gets....

`(7.30*mol+2xx8.05*mol)xxunderbrace(44.01*g*mol^-1)_"molar mass of carbon dioxide"~=1*kg`

Take that environment....