# Question 67ca3

Feb 12, 2018

$0.05$ moles of ${N}_{2} {H}_{6} C {O}_{2}$

#### Explanation:

Well, we would first need to calculate the molar mass of ${N}_{2} {H}_{6} C {O}_{2}$.

$N$ has a molar mass of $14 g \text{/} m o l$.

$\therefore {N}_{2}$ has a molar mass of $28 g \text{/} m o l$.

$H$ has a molar mass of $1 g \text{/} m o l$.

$\therefore {H}_{6}$ has a molar mass of $6 g \text{/} m o l$.

$C {O}_{2}$ has a molar mass of $44 g \text{/} m o l$.

$\therefore {N}_{2} {H}_{6} C {O}_{2}$ has a molar mass of $28 + 6 + 44 = 78 g \text{/} m o l$.

$\text{moles"="mass"/"molar mass}$

:."moles"=(4cancelg)/(78cancelg"/"mol)=0.05mol#