# Question #34828

Feb 9, 2018

$\frac{4}{{x}^{2} + 1}$

#### Explanation:

First, take the LCM and then solve it like any other expression.

$\frac{3 x + 2}{{x}^{2} + 1} - \frac{3 x - 2}{{x}^{2} + 1}$

$= \frac{3 x + 2 - 3 x + 2}{{x}^{2} + 1}$

On solving, you will get:

$\frac{4}{{x}^{2} + 1}$