Question

Question #26240

Answer 1

`"please review the details below."`

Explanation:

`"The sum of the momentums before the hammer was thrown."`

`v_a=0`
`m_a=70 kg`

`v_h=0`
`m_h=4kg`

`P_b=m_a*v_a+m_h*v_h`
`P_b=70*0+4*0=0`

`"The sum of the momentums after the hammer was thrown."`

`m_a=70kg`
`v_a=3 ms^-1`

`m_h=4kg`
`v_h=v=?`

`P_a=m_a*v_a+m_h*v_h`

`P_a=70*3+4v`

`P_a=210+4v`

`"Since the momentum is conserved, we can write the following equation."`

`P_b=P_a`

`0=210+4v`
`-210=4v`

`v=-210/4`

`v=-52.5 ms^-1" should be thrown in the opposite direction."`