Find the integral of #1+x-x^2-x^3#?

1 Answer
Feb 15, 2018

#int(1+x-x^2-x^3)dx=x+x^2/2-x^3/3-x^4/4+c#

Explanation:

As #intx^ndx=x^(n+1)/(n+1)#

#int(1+x-x^2-x^3)dx#

= #intdx+intxdx-intx^2dx-intx^3dx+c#

= #x+x^2/2-x^3/3-x^4/4+c#

We add #c#, a constant, as derivative of constant is #0#.