# (6, n) is a solution to the inequality y+3<= (x-4). Is 3 a possible value for n?

Jul 22, 2018

$\textcolor{b l u e}{\text{No}}$

#### Explanation:

$y + 3 \le x - 4$

$y \le x - 4 - 3$

$y \le x - 7$

Plugging in $x = 6$

$y \le 6 - 7$

$y \le - 1$

If $x = 6$ the possible values of $n$ are in the interval:

$\left(- \infty , - 1\right]$

So $3$ is not a possible value for $n$: