Question

8 g NaOH is dissolved in 250 ml solution. If solution is diluted to 500 ml then moles of NaOH and molarity of dilute solution would be ?

Answer 1

The concentration would be halved....

Explanation:

In either scenatio, we gots `"concentration"="moles of solute"/"volume of solution"`

`"concentration"_1=((8.0*g)/(40.0*g*mol^-1))/(250*mLxx10^-3*L*mL^-1)`

`=0.80*mol*L^-1`

`"concentration"_2=((8.0*g)/(40.0*g*mol^-1))/(500*mLxx10^-3*L*mL^-1)`

`=0.40*mol*L^-1`...