# ((a^2+ax+x^2)/(ax+2ay)) ÷( (a^3−x^3)/(bx+2by))# ?

1 Answer
Mar 23, 2017

Answer:

I tried this:

Explanation:

I would try changing the division into a mutiplication inverting the second fraction:
#(a^2+ax+x^2)/(ax+2ay)color(red)(xx((bx+2by)/(a^3-x^3))#
I would then try to rearrange collecting:
#(a^2+ax+x^2)/(acancel((x+2y)))xx(bcancel((x+2y)))/(a^3-x^3)#
#(a^2+ax+x^2)/(a)xx(b)/(a^3-x^3)#

we can write:
#a^3-x^3=(a-x)(a^2+ax+b^2)#
so we get:
#cancel(a^2+ax+x^2)/(a)xx(b)/((a-x)cancel(a^2+ax+b^2))=#
#=b/(a(a-x)#