A 20.0 mL sample of a gas is at 546 K and has a pressure of 6.0 atm. If the temperature is changed to 273 K and the pressure to 2.0 atm, the new volume of the gas is what?

1 Answer
Dec 15, 2016

Answer:

#(P_1V_1)/T_1=(P_2V_2)/T_2#, given constant #n#, so............

Explanation:

#V_2=(P_1xxV_1xxT_2)/(P_2xxT_1)#

We immediately see that we will get an answer in #"terms of volume"#, so we're batting on a firm wicket.

#V_2=(6.0*atmxx20.0*mLxx273*K)/(2.0*atmxx546*K)=??*mL#