A=2015(1+2+3+.....2014) B=2014(1+2+3+.....2015) Compare A and B ?

2 Answers
Mar 15, 2017

Answer:

#B# is greater than #A#

Explanation:

Sum of the series #1+2+3+4+...............+n=(n(n+1))/2#

Hence #A=2015(1+2+3+4+...............+2014)#

= #2015xx(2014xx2015)/2=2015xx2014xx2015/2#

and #B=2014(1+2+3+4+...............+2015)#

= #2014xx(2015xx2016)/2=2015xx2014xx2016/2#

It is evident that #B>A#

Mar 15, 2017

Answer:

#B > A#

Explanation:

#A-B=2015(1+2+cdots+2014)-(2014(1+2+cdots+2014)+2014 cdot 2015)=-2014 cdot 2015#

then if #A-B=-2014 cdot 2015->B > A#