Question

A=2015(1+2+3+.....2014) B=2014(1+2+3+.....2015) Compare A and B ?

Answer 1

`B` is greater than `A`

Explanation:

Sum of the series `1+2+3+4+...............+n=(n(n+1))/2`

Hence `A=2015(1+2+3+4+...............+2014)`

= `2015xx(2014xx2015)/2=2015xx2014xx2015/2`

and `B=2014(1+2+3+4+...............+2015)`

= `2014xx(2015xx2016)/2=2015xx2014xx2016/2`

It is evident that `B>A`

Answer 2

`B > A`

Explanation:

`A-B=2015(1+2+cdots+2014)-(2014(1+2+cdots+2014)+2014 cdot 2015)=-2014 cdot 2015`

then if `A-B=-2014 cdot 2015->B > A`