A 23 kg body is moving through space in the positive direction of an x axis with a speed of 220 m/s when, due to an internal explosion, it breaks into three parts. ?

1 Answer
Aug 30, 2016

Question

A 23 kg body is moving through space in the positive direction of an x axis with a speed of 220 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 13 kg, moves away from the point of explosion with a speed of 110 m/s in the positive y direction. A second part, with a mass of 2.8 kg, moves in the negative x direction with a speed of 310 m/s. What are the (a) x-component and (b) y-component of the velocity of the third part? (c) How much energy is released in the explosion? Ignore effects due to the gravitational force.

Answer

Mass of unbroken body #= 23kg#
Its velocity along +ve x-axis #v=220m/s#

Mass of 1st broken part #m_1= 13kg#

Its velocity along +ve y-axis #v_1=110m/s#

Mass of 2nd broken part #m_2= 2.8kg#

Its velocity along -ve x-axis
#v_2=310m/s#

Mass of 3rd broken part #m_3= (23-13-2.8)kg=7.2kg#

Let its velocity along x-axis be #v_x# and along y-axis be #v_y#

Applying conservation of momentum along x direction

#m_1xx0+m_2xx(-310)+m_3xxv_x=23xx220#

#=>-2.8xx310+7.2xxv_x=23xx220#

(a)#=>v_x=(23xx220+2.8xx310)/7.2=823.3m/s#

Applying conservation of momentum along y direction

#m_1xx110+m_2xx0+m_3xxv_y=0#

#=>13xx110+2.8xx0+7.2xxv_y=0#

(b)#=>v_y=(-13*110)/7.2=-198.6m/s#

Energy released or Change in KE

#=(1/2(13*110^2+2.8*310^2+7.2*823.3^2+7.2*198.6^2) -1/2*23*220^2)J#