# #a+3/(4b)=2# and #b+3/(4a)=6#. How do you find #b/a#?

##### 1 Answer

Mar 10, 2016

#### Explanation:

If we just examine the first equation:

#(4ab)/(4b)+3/(4b)=2#

#(4ab+3)/(4b)=2#

The second equation, modified similarly, yields:

#(4ab+3)/(4a)=6#

If we take the second equation divided by the first equation, we see that

#((4ab+3)/(4a))/((4ab+3)/(4b))=6/2#

#(4b)/(4a)=3#

#b/a=3#