Question

A 300g ball at rest is struck with a bat with a force of 150N. If the bat was in contact with the ball, for 0.02 seconds, what is the ball's velocity?

Answer 1

`vf=10 m/s`

Explanation:

We will use the impulse formula
`Ftrianglet=mtrianglev`
`(Ftrianglet)/m=vf-vi`
Since vi is zero, solve for vf
`(150N*.02 s)/(0.30 kg)=vf`
`vf=10 m/s`