# A 4.0 g sample of iron was heated from 0°C to 20°C. It absorbed 35.2 J of energy as heat. What is the specific heat of this piece of iron?

Jun 27, 2016

The specific heat capacity of the iron is $\text{0.44 J·°C"^"-1""g"^"-1}$.

#### Explanation:

The formula for the heat absorbed by a substance is

color(blue)(|bar(ul(color(white)(a/a) q = mcΔT color(white)(a/a)|)))" "

where

$q$ is the quantity of heat

$m$ is the mass of the substance

$c$ is the specific heat capacity of the material

ΔT is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

c = q/(mΔT)

ΔT = "(20 - 0) °C" = "20 °C"

$c = \text{35.2 J"/"4.0 g × 20 °C" = "0.44 J·°C"^"-1""g"^"-1}$