# A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s, what is the force exerted by the rope on the bucket of water?

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Apr 5, 2018

#### Answer:

$65$ [N]

#### Explanation:

Assuming the upward acceleration reads $3$ [m$/ {\text{s}}^{2}$] we have

$T - m g = m a$ or

$T = m \left(g + a\right) = 5 \left(10 + 3\right) = 65$ [N]

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