# A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s, what is the force exerted by the rope on the bucket of water?

Apr 5, 2018

$65$ [N]
Assuming the upward acceleration reads $3$ [m$/ {\text{s}}^{2}$] we have
$T - m g = m a$ or
$T = m \left(g + a\right) = 5 \left(10 + 3\right) = 65$ [N]