# A 50 kg skater pushed by a friend accelerates at 5 m/s. How much force did the friend apply?

Nov 4, 2017

$F = 250 N$

#### Explanation:

$F = m a$ -----Newton's second law.

We know : $m = 50 k g \mathmr{and} a = 5 \frac{m}{s} ^ 2$

$\therefore F = 50 k g \times 5 \frac{m}{s} ^ 2 = 250 N$

$F = 250 N$

Nov 4, 2017

$250$ $N$

#### Explanation:

To solve this, we use Newton's second law of motion

color(blue)("Force"="Mass"xx"Acceleration" $\left(F = m a\right)$

We know that

color(brown)("Mass"=50 color(brown)(kg

color(brown)("Acceleration"=5 color(brown)(m/s^2

So,

$\rightarrow 50 \times 5$

color(green)(rArr250 color(green)(N

So the skater pushed his friend with a force of $250$ $N$

Hope this helps!!! ☺§☻