A 5500-kg freight truck accelerates from 4.2 m/s to 7.8 m/s in 15.0 s by the application of a constant force. What change in momentum occurs?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

1
May 5, 2018

Change in momentum is $19800$ $k g . \frac{m}{s}$

Explanation:

As initial velocity is $4.2 \frac{m}{s}$ and final velocity is $7.8 \frac{m}{s}$

Initial momentum is $5500 \times 4.2 = 23100$ $k g . \frac{m}{s}$ and

final momentum is $5500 \times 7.8 = 42900$ $k g . \frac{m}{s}$

$\therefore$ Change in momentum is $42900 - 23100 = 19800$ $k g . \frac{m}{s}$

• 19 minutes ago
• 19 minutes ago
• 23 minutes ago
• 42 minutes ago
• 2 minutes ago
• 8 minutes ago
• 10 minutes ago
• 12 minutes ago
• 16 minutes ago
• 17 minutes ago
• 19 minutes ago
• 19 minutes ago
• 23 minutes ago
• 42 minutes ago