# A 5500-kg freight truck accelerates from 4.2 m/s to 7.8 m/s in 15.0 s by the application of a constant force. What change in momentum occurs?

May 5, 2018

Change in momentum is $19800$ $k g . \frac{m}{s}$

#### Explanation:

As initial velocity is $4.2 \frac{m}{s}$ and final velocity is $7.8 \frac{m}{s}$

Initial momentum is $5500 \times 4.2 = 23100$ $k g . \frac{m}{s}$ and

final momentum is $5500 \times 7.8 = 42900$ $k g . \frac{m}{s}$

$\therefore$ Change in momentum is $42900 - 23100 = 19800$ $k g . \frac{m}{s}$