A 60 W kitchen light is left on for an entire year. If the cost of electricity is $0.08 per kWxh, what did it cost to leave on the light bulb ?

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Apr 12, 2018

Answer:

#$42.08#, or #$42.05#

Explanation:

#1W# is #1# watt. #1# watt of power means that #1# joule of energy is used in #1# second. therefore, the number of watts shows how many joules of energy are used in a second.

#1 kW# is #1000# watts. this means that #1000# joules of energy are used in #1# second.

#1 kWh# shows the amount of energy used at the same rate of #1kW# in an hour. #1kW# means that #1000# joules are used in a second.

#1# hour is #3600# seconds. therefore, #1000# joules per second is the same rate as #3600 * 1000# joules per hour.

#3600 * 1000 = 3,600,000#

therefore, #1 kWh# is equal to #3,600,000# joules.

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in a #60W# light bulb, #60# joules are used every second.

if you count #1# year as #365.25# days, then #1# year has #31,557,600# seconds.

if #60# joules are used per second, then #1,893,456,000# joules are used in #31,557,600# seconds.

#1kWh# is #3,600,000# joules.

#1,893,456,000# joules is #(1,893,456,000)/(3,600,000) kWh#. this is #525.96 kWh#.

#$0.08 * 525.96# is #$42.08# to #2# decimal places.
if the #60W# light bulb is left on for #365.25# days, then it will cost #$42.08#.

if you count #1# year as #365# days, then #1# year has #31,536,000# seconds.

if #60# joules are used per second, then #1,892,160,000# joules are used in #31,536,000# seconds.

#1kWh# is #3,600,000# joules.

#1,892,160,000# joules is #(1,892,160,000)/(3,600,000) kWh#. this is #525.6 kWh#.

#$0.08 * 525.6# is #$42.05# to #2# decimal places.
if the #60W# light bulb is left on for #365.25# days, then it will cost #$42.05#.

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