Question

A 7.3 kg bowling ball and a 8.1 kg bowling ball rest on a rack 1.27 m apart. At what separation is the force of gravity between the balls equal to `2.0*10^-9` `N`?

Answer 1

`1,407m`

Explanation:

Using Newton's Law of Universal Gravitational Attraction, we get

`F=G(m_1m_2)/r^2`

`thereforer=sqrt((Gm_1m_2)/F)`

`=sqrt(((6,7xx10^(-11))(7,3)(8,1))/(2xx10^(-9))`

`=1,407m`