# A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. What is the diver's kinetic energy?

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Gió Share
Jan 11, 2017

I got $224 , 676 J$

#### Explanation:

Kinetic Energy $K$ is given as:
$K = \frac{1}{2} m {v}^{2}$
Using mass $m$ and velocity given we get:

$K = \frac{1}{2} \cdot 72 \cdot {\left(79\right)}^{2} = 224 , 676 J$

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