Question

A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. What is the diver's kinetic energy?

Answer 1

I got `224,676J`

Explanation:

Kinetic Energy `K` is given as:
`K=1/2mv^2`
Using mass `m` and velocity given we get:

`K=1/2*72*(79)^2=224,676J`