# A 775 ml sample of nitrogen gas is cooled from 67"^@C to 42"^@C. What is the new volume if the pressure remains the same?

Apr 3, 2017

The new volume is $= 718 m L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

Volume, ${V}_{1} = 0.775 L$

Temperature, ${T}_{1} = 67 + 273 = 340 K$

Temperature, ${T}_{2} = 42 + 273 = 315 K$

So,

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1}$

$= \frac{315}{340} \cdot 0.775 = 0.718 L$