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A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of first drawing a blue marble and then, without replacing it, drawing a red marble?

1 Answer
Mar 5, 2018

Answer:

#color(red)(=3/38#

Explanation:

Probability = no. of favourable outcomes /total no. of outcomes

Probability of getting a blue marble#=5/(5+6+9)=color (Magenta)(5/20#

Probability of getting a red marble#=6/(20-1)=##color (Magenta)(6/19#

#5/20xx6/19#

#color(red)(=3/38#

~Hope this helps! :)