A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of first drawing a blue marble and then, without replacing it, drawing a red marble?

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Mar 7, 2018

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#color(red)(=3/38#

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Probability = no. of favourable outcomes /total no. of outcomes

Probability of getting a blue marble#=5/(5+6+9)=color (Magenta)(5/20#

Probability of getting a red marble#=6/(20-1)=##color (Magenta)(6/19#

#5/20xx6/19#

#color(red)(=3/38#

~Hope this helps! :)

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