A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random. What is the probability of first drawing a blue marble and then, without replacing it, drawing a red marble?

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Mar 7, 2018

Answer:

color(red)(=3/38

Explanation:

Probability = no. of favourable outcomes /total no. of outcomes

Probability of getting a blue marble=5/(5+6+9)=color (Magenta)(5/20

Probability of getting a red marble$= \frac{6}{20 - 1} =$color (Magenta)(6/19

$\frac{5}{20} \times \frac{6}{19}$

color(red)(=3/38

~Hope this helps! :)

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