# A balanced lever has two weights on it, one with mass 6 kg and one with mass 5 kg. If the first weight is  3 m from the fulcrum, how far is the second weight from the fulcrum?

Jul 9, 2017

The distance is $= 3.6 m$

#### Explanation:

The mass ${M}_{1} = 6 k g$

The mass ${M}_{2} = 5 k g$

The distance $a = 3 m$

Taking moments about the fulcrum

${M}_{1} \cdot a = {M}_{2} \cdot b$

$b = {M}_{1} / {M}_{2} \cdot a = \frac{6 g}{5 g} \cdot 3 = \frac{18}{5} = 3.6 m$