# A balanced lever has two weights on it, the first with mass 16 kg  and the second with mass 32 kg. If the first weight is  7 m from the fulcrum, how far is the second weight from the fulcrum?

##### 1 Answer
Dec 21, 2016

Second weight is $3.5$ $m .$ from the fulcrum.

#### Explanation:

In a balanced lever, the moment of each of the weights should be equal.

Moment is mass of the weight multiplied by its distance from fulcrum.

As first weighs $16 k g .$ and is at a distance of $7 m$ frm fulcrum, its moment is $16 \times 7 = 112$ $k g . m$.

As lever is balanced, moment of second weight too would be $112$ $k g . m$. But its weight is $32 k g .$.

Hence, it should be at a distance of

$\frac{112}{32} = \frac{16 \times 7}{16 \times 2} = \frac{7}{2} = 3.5$ $m .$