# A balanced lever has two weights on it, the first with mass 16 kg  and the second with mass 3 kg. If the first weight is  7 m from the fulcrum, how far is the second weight from the fulcrum?

Apr 28, 2016

$\frac{112}{3} m$

#### Explanation:

Well, if the lever is balanced, the torque (or, the moment of force) has to be the same. Hence,

$16 \cdot 7 m = 3 \cdot x$

$\implies x = \frac{112}{3} m$

• why can't I have some nice numbers, in the problem so that, at least the results look nice ??