# A balanced lever has two weights on it, the first with mass 5 kg  and the second with mass 8 kg. If the first weight is  12 m from the fulcrum, how far is the second weight from the fulcrum?

Apr 22, 2016

$7.5$ $m$

#### Explanation:

1st load ${M}_{1}$ = $5$ $k g$
distance from fulcrum $a$ = $12$ $m$
2nd load ${M}_{2}$ = $8$ $k g$
distance from fulcrum $b$ = ?

We have,
${M}_{1}$ x $a$ = ${M}_{2}$ x $b$
now solve for $b$

solving $b = 7.5$ $m$