# A balanced lever has two weights on it, the first with mass 6 kg  and the second with mass 4 kg. If the first weight is  5 m from the fulcrum, how far is the second weight from the fulcrum?

Feb 25, 2016

Second weight is $7.5$ $m$ far from fulcrum.

#### Explanation:

Let the the second weight be $x$ $m$ far from the fulcrum.

As the lever is balanced, moment ($M = F \cdot d$, where $F$ is force applied and $d$ is its distance from fulcrum) of the two weights should be equal.

Moment of first weight is $6 \cdot 5 = 30$ and as it balances second weight of $4$ kg, the latter's distance should be

$\frac{30}{4} = 7.5$ $m$.