# A balanced lever has two weights on it, the first with mass 6 kg  and the second with mass 27 kg. If the first weight is  8 m from the fulcrum, how far is the second weight from the fulcrum?

$\frac{16}{9} = 1 \frac{7}{9}$ m.
6 " kgm" xx 8 " m" = 27 " kgm" xx ?
?= (6 cancel(" kgm")xx8 " m")/(27 cancel(" kgm")) = (2xx8 " m")/9 = 16/9 " m"