# A balanced lever has two weights on it, the first with mass 7 kg  and the second with mass 3 kg. If the first weight is  2 m from the fulcrum, how far is the second weight from the fulcrum?

$4.667$ meters
In a balanced lever, product of mass of one weight and its distance from fulcrum is equal to the mass of other weight and its distance from the fulcrum. As the product is $14$ in first weight, the distance of second weight from fulcrum would be $\frac{14}{3}$ i.e. $4.667$ meters.