# A ball with a mass of #420 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #18 (kg)/s^2# and was compressed by #6/5 m# when the ball was released. How high will the ball go?

##### 1 Answer

Apr 16, 2016

#### Explanation:

By conservation of mechanical energy

PE of the ball at its maximum height when projected by the spring will be equal to PE of the contracted spring

If h m be the max height attained by the ball then

where

- m= mass = 0.42kg
- g = acceleration due to gravity
#= 9.8m/s^2# - h = maximum height =?
- k = force constant of spring =
#18(kg)/s^2# - x=compression of spring =
#6/5m=1.2m#