A ball with a mass of #420 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #18 (kg)/s^2# and was compressed by #6/5 m# when the ball was released. How high will the ball go?
1 Answer
Apr 16, 2016
Explanation:
By conservation of mechanical energy
PE of the ball at its maximum height when projected by the spring will be equal to PE of the contracted spring
If h m be the max height attained by the ball then
where
- m= mass = 0.42kg
- g = acceleration due to gravity
#= 9.8m/s^2# - h = maximum height =?
- k = force constant of spring =
#18(kg)/s^2# - x=compression of spring =
#6/5m=1.2m#
