A ball with a mass of #450 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #27 (kg)/s^2# and was compressed by #9/8 m# when the ball was released. How high will the ball go?

Question

909 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-11T11:39:49

The height is #=3.87m#

enter image source here

The spring constant is #k=27kgs^-2#

The compression is #x=9/8m#

The potential energy in the spring is

#PE=1/2*27*(9/8)^2=17.09J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=17.09=0.45*9.8*h#

#h=17.09*1/(0.45*9.8)#

#=3.87m#