A ball with a mass of #480 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #24 (kg)/s^2# and was compressed by #7/8 m# when the ball was released. How high will the ball go?

1 Answer
Jun 5, 2017

Answer:

The height is #=1.95m#

Explanation:

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The spring constant is #k=24kgs^-2#

The compression is #x=7/8m#

The potentialenergy in the spring is

#PE=1/2*24*(7/8)^2=9.1875J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=9.1875=0.48*9.8*h#

#h=9.1875*1/(0.48*9.8)#

#=1.95m#